Design and simplified calibration of a Mueller imaging polarimeter for material classification

Yvain Quéau; Florian Leporcq; Ayman Alfalou

doi:10.1364/OL.43.004941

Optics Letters
Vol. 43,
Issue 20,
pp. 4941-4944
(2018)
•https://doi.org/10.1364/OL.43.004941

Design and simplified calibration of a Mueller imaging polarimeter for material classification

Yvain Quéau, Florian Leporcq, and Ayman Alfalou

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Yvain Quéau, Florian Leporcq, and Ayman Alfalou, "Design and simplified calibration of a Mueller imaging polarimeter for material classification," Opt. Lett. 43, 4941-4944 (2018)

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Abstract

This study is concerned with the design of a Mueller imaging polarimeter for the visualization of spatially varying Mueller matrix fields. A simplified calibration procedure is advocated, where all the optical elements are calibrated simultaneously rather than independently as in the state of the art. This is shown to significantly reduce the bias inherent to sequential calibration methods. In addition, this procedure requires no reference sample, it allows calibration both in transmission or in reflection modes, and it relies on ready-to-use cameras. Put together, these novelties should help nonspecialists in optics in designing and calibrating a Mueller imaging polarimeter for applications such as material classification.

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$M_{seq}^{air} = [\begin{matrix} 1.000 & 0.010 & 0.004 & 0.001 \\ 0.002 & 0.991 & - 0.015 & 0.009 \\ - 0.007 & 0.010 & 0.992 & - 0.004 \\ 0.001 & - 0.005 & - 0.001 & 0.997 \end{matrix}]$	$\frac{‖ M_{seq}^{air} - M^{air} ‖_{F}}{‖ M^{air} ‖_{F}} = 0.015$	$M_{bun}^{air} = [\begin{matrix} 1.000 & 0.000 & 0.003 & - 0.003 \\ - 0.007 & 1.002 & - 0.010 & 0.011 \\ - 0.007 & 0.007 & 1.005 & - 0.002 \\ 0.003 & - 0.002 & 0.003 & 0.996 \end{matrix}]$	$\frac{‖ M_{bun}^{air} - M^{air} ‖_{F}}{‖ M^{air} ‖_{F}} = 0.011$
$M_{seq}^{mirr} = [\begin{matrix} 1.000 & 0.008 & - 0.010 & 0.003 \\ 0.007 & 0.983 & 0.016 & - 0.006 \\ - 0.003 & 0.018 & - 0.994 & 0.015 \\ - 0.002 & - 0.005 & - 0.016 & - 1.002 \end{matrix}]$	$\frac{‖ M_{seq}^{mirr} - M^{mirr} ‖_{F}}{‖ M^{mirr} ‖_{F}} = 0.021$	$M_{bun}^{mirr} = [\begin{matrix} 1.000 & 0.004 & - 0.004 & 0.004 \\ - 0.001 & 1.000 & 0.000 & - 0.005 \\ 0.007 & 0.000 & - 1.009 & 0.014 \\ - 0.003 & - 0.000 & - 0.017 & - 0.998 \end{matrix}]$	$\frac{‖ M_{bun}^{mirr} - M^{mirr} ‖_{F}}{‖ M^{mirr} ‖_{F}} = 0.013$

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